← Back to Topic 9Print all levels + keys

Grade 8 Algebra: Solving Systems by Substitution

Name: ______________________Date: ____________Score: ____ / 8

Level 3

Isolate first; special cases

  1. 1. Solve by substitution:
    {x+y=72x−y=2\begin{cases} x + y = 7 \\ 2x - y = 2 \end{cases}
  2. 2. Solve by substitution:
    {x−2y=13x+y=10\begin{cases} x - 2y = 1 \\ 3x + y = 10 \end{cases}
  3. 3. Solve by substitution:
    {2x+y=−14x−3y=13\begin{cases} 2x + y = -1 \\ 4x - 3y = 13 \end{cases}
  4. 4. Solve by substitution:
    {y=2x+54x−2y=6\begin{cases} y = 2x + 5 \\ 4x - 2y = 6 \end{cases}
  5. 5. Solve by substitution:
    {y=3x−16x−2y=2\begin{cases} y = 3x - 1 \\ 6x - 2y = 2 \end{cases}
  6. 6. Solve by substitution:
    {x+3y=42x−y=−6\begin{cases} x + 3y = 4 \\ 2x - y = -6 \end{cases}
  7. 7. Solve by substitution:
    {3x+2y=8x−y=6\begin{cases} 3x + 2y = 8 \\ x - y = 6 \end{cases}
  8. 8. Solve by substitution:
    {y=12x+2x+2y=12\begin{cases} y = \tfrac{1}{2}x + 2 \\ x + 2y = 12 \end{cases}