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Grade 8 Algebra: Solving Systems by Substitution

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Level 2

Negatives and coefficients

  1. 1. Solve by substitution:
    {y=−2x+33x+y=5\begin{cases} y = -2x + 3 \\ 3x + y = 5 \end{cases}
  2. 2. Solve by substitution:
    {y=x−42x+3y=3\begin{cases} y = x - 4 \\ 2x + 3y = 3 \end{cases}
  3. 3. Solve by substitution:
    {x=2y−13x−y=7\begin{cases} x = 2y - 1 \\ 3x - y = 7 \end{cases}
  4. 4. Solve by substitution:
    {y=3x+24x−y=−5\begin{cases} y = 3x + 2 \\ 4x - y = -5 \end{cases}
  5. 5. Solve by substitution:
    {x=−y+62x−3y=−3\begin{cases} x = -y + 6 \\ 2x - 3y = -3 \end{cases}
  6. 6. Solve by substitution:
    {y=−x−15x+2y=4\begin{cases} y = -x - 1 \\ 5x + 2y = 4 \end{cases}
  7. 7. Solve by substitution:
    {y=2x−3y=−x+6\begin{cases} y = 2x - 3 \\ y = -x + 6 \end{cases}
  8. 8. Solve by substitution:
    {x=4y2x−5y=−6\begin{cases} x = 4y \\ 2x - 5y = -6 \end{cases}